Problema Solution
Pipe A can fill a tank in 30 mins and Pipe B can fill it in 28 mins.If 3/4th of the tank is filled by Pipe B alone and both are
opened, how much time is required by both the pipes to fill the tank completely ?
Answer provided by our tutors
Pipe A filling rate:1/30 tank/min
Pipe B filling rate:1/28 tank/min
Combined filling rate: 1/30 + 1/28 tank/min
Together they fill 1/4 of the tank. Let t be the time required.
(1/30 +1/28)t = 1/4
t = (1/4)(30*28)/(28+30) = 105/29 min ~ 3.62 min
Answer:3.62 min is required by both the pipes to fill the tank completely.