Select any two integers between -12 and +12 which will become solutions to a system of two equations.

I select 2,3.

Write TWO EQUATIONS that have your two integers as solutions.

x+y = 5

2x-y = 1

Use the Addition/Subtraction method. Make sure you show the necessary 5 steps, which are:

1- If necessary, write both equations in the form ax=by+c

x = -y + 5

2x = y + 1

2- multiply one or two equations by nubers so that the absolute values of either the coefficients of the x terms or the y terms are alike.

We don't need to do anything since the abloute values of the coefficients on the ys are the same.

x = -y + 5

2x = y + 1

3- Eliminate one of the variables by adding the equations if the signs of the coefficients of the variable are different. Subtract the equations if the signs of the coefficients of the variable are the same.

We add the 2 equations to each other to get:

3x = 6

4- Solve the resultant equation for the remaining variable. 5- Select one equation from the original 2 equations, substitute the value of the variable found in step 4, and solve for the other variable.

3x = 6

Divide both sides by 3 to get

x = 2. Plug this in to 2x = y + 1 to get

2(2) = y+ 1

4 = y + 1

3 = y

Therefore we have x = 2, y = 3 as desired.

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