Problema Solution
In three days, Carter drove 2196 miles in 36 hours behind the wheel. the first day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the third day than on the first day, then how many hours did he drive each day?
Answer provided by our tutors
Let X be the hours driven on day 1, Y hours on day 2 and Z hours on day 3
then:
X + Y + Z = 36
Average speed * hours/day = miles driven/day so
64X + 62Y + 58Z = 2196
We know he drove 4 more hours on day 3 than day 1 so
X + 4 = Z
Now substitute in both equations
X + Y + X + 4 = 36
64X + 62Y + 58(X + 4) = 2196
Combine terms
2X + Y = 32
122X + 62Y = 1964
Now solve for Y in Eq 1
Y = 32 - 2X
and substitute in final equation
122X + 62(32-2X) = 1964
Combine terms to solve for X and use answer to compute Y and then Z