Problema Solution
Find three consecutive odd integers such that twice the sum of the first and the second is equal to four times the sum of the second and the third.
Answer provided by our tutors
Let the first integer be x, the second be x + 1, and the third be x + 2. So we have:
2x + 4(x + 1) = 2(x + 2) + 20
2x + 4x + 4 = 2x + 4 + 20
4x = 20
x = 5
x + 1 = 6
x + 2 = 7
Thus these numbers are 5, 6, and 7