Problema Solution

Find the fewest number of squares, each with a perimeter of 8", that would completely cover a square with a side of 8".

Answer provided by our tutors

Find the fewest number of squares, each with a perimeter of 8", that would completely cover a square with a side of 8".

Arae of square of side 8"=8*8=64 sq in.

Perimter of small square =8".

4s=8".

s=8/4=2".

Area of small square =2*2=4 sq in.

Number of 2 in size square fit in  square of are 64 square in =64/4 =16.