Problema Solution
Find the fewest number of squares, each with a perimeter of 8", that would completely cover a square with a side of 8".
Answer provided by our tutors
Find the fewest number of squares, each with a perimeter of 8", that would completely cover a square with a side of 8".
Arae of square of side 8"=8*8=64 sq in.
Perimter of small square =8".
4s=8".
s=8/4=2".
Area of small square =2*2=4 sq in.
Number of 2 in size square fit in square of are 64 square in =64/4 =16.