Problema Solution
john travels at a speed of 42 mph. for the first part of his trip. The second part of his trip was twice the distance of the first part and he traveled at a speed of 68 mph. If the total distance a 267 miles, how for was the first leg of his trip?
Answer provided by our tutors
d1 = r1t1 = 42t
d2 = 2d1 = 68t2
dtotal = d1 + d2 = 267
42t + 2(42t) = 267
126t = 267
t = 89/42
d1 = first leg of his trip = rt = 42(89/42) = 89 miles --> final answer