Problema Solution
Factor the following expression into a product of two binomials
121x^2-132X+36
Answer provided by our tutors
121x^2-132X+36
= (11x)^2 - 2*11*6x +6^2
= (11x-6)(11x-6)
= (11x-6)^2
Factor the following expression into a product of two binomials
121x^2-132X+36
121x^2-132X+36
= (11x)^2 - 2*11*6x +6^2
= (11x-6)(11x-6)
= (11x-6)^2