find 4 consecutive even integers such that the sum of twice the first, five times the second and four times the third divided by three times the fourth equals 3.

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4 consecutive integers: x, x+2, x+4, x+6

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Write an equation for the statement:

"the sum of twice the first, five times the second and four times the third divided by three times the fourth equals 3."

 = 3

:

 = 3

:

 = 3

Multiply both sides by (3x+18)

11x + 26 = 3(3x + 18)

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11x + 26 = 9x + 54

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11x - 9x = 54 - 26

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2x = 28

x = 

x = 14

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The four numbers: 14, 16, 18, 20

Check the solutions in the statement:

"the sum of twice the first, five times the second and four times the third divided by three times the fourth equals 3."

 = 3

 = 3

 = 3

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2) Find three consecutive odd integers such that 4 less than twice the second has the same value as three times the number that is one more that the third.

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We have: x, (x+2), (x+4) as the three consecutive odd numbers

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2(x+2)- 4 = 3(x+4+1)

2x + 4 - 4 = 3(x+5)

2x = 3x + 15

2x = 3x = 15

-x = 15

x = -15

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The numbers: -15, -13, -11

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;

Check:

2(-13) - 4 = 3(-11+1)

-26 - 4 = 3(-10)