Problema Solution
Write the standard form of the equation of the line passing through the point (2,-2)and perpendicular to the line x-6y=-10
Answer provided by our tutors
The given line can be written as:
6y = x + 10
y = (1/6)x+10/6
Slope = 1/6
The perpendicular line would have slope =-6
Equation of the line is given as:
(y--2)=-6(x-2)
y+2 = -6x + 12
y = -6x + 10