Problema Solution
Given three consecutive odd integers, the product of the first and third is qual to four less than nine times the second.
Answer provided by our tutors
Let the integers be x, x+2, x+4.
x(x+4) = 9(x+2) - 4
x^2 + 4x = 9x +18 - 4
x^2 -5x - 14 = 0
(x-7)(x+2)=0
solutions: x=7, x=-2 (not an integer because it's negative)
three integers are: 7,9,11