Problema Solution
If the area of a rectangle is x^2+13x+42 and the length is x+6, what is the width?
Answer provided by our tutors
Let:
x^2 + 13x + 42 - area of rectangle
x+6 - length
--> area = width * length
x^2 + 13x + 42 = x^2 + 6x + 7x + 42
= x (x+6) + 7 (x+6)
= (x+6)(x+7)
--> width = (x+6)(x+7)/(x+6) = x+7