Problema Solution
Sarah has a collection of nickels, dimes, and quarters worth $15.10. She has 10 more dimes than nickels and twice as many quarters as dimes. How many coins of each kind does she have?
Answer provided by our tutors
let x represent the number of nickels.
As she has 10 more dimes than nickels, the number of dimes is x + 10.
As she has twice as many quarters as dimes, the number of quarters is 2(x + 10)
the total value is $15.10, so I get an equation:
0.05x + 0.1*(x + 10) + 0.25*2(x + 10) = 15.10
0.05x + 0.1x + 1 + 0.5x + 5 = 15.10
0.65x = 9.1
x = 14
x + 10 = 24
2(x + 10) = 48
there are 14 nickes, 24 dimes and 48 quarters