Problema Solution
the second angle of a triangular building lot is three times as large as the first the third angle is 10 degrees more than the sum of the other two angles find the measure of the third angle
Answer provided by our tutors
Let x = measure of first angle
then
3x = second angle
(x + 3x + 10) = third angle
.
sum of interior angles of a triangle is 180:
x + 3x + x+3x+10 = 180
8x+10 = 180
8x = 170
x = 21.25 deg (first)
.
second:
3x = 3(21.25) = 63.75 deg
.
third:
(x + 3x + 10) = (21.25 + 3(21.25) + 10) = 95 deg