Problema Solution
The width of a dock is 4m less than the length.The area is 21m2.
Answer provided by our tutors
let the length be x and the width be y
length = x
width = y
width is 4m less than length so
y = x-4
area is given by length*width
so 21 = x*y
21 = x(x-4)
21 = x2-4x get the equation to equal zero
x2-4x-21 = 0 factor this
(x-7)(x+3) = 0 set each part equal to zero
x-7 = 0 or x+3 = 0
x = 7 or x = -3
length can't be negative, so use x=7
substitute this back into the equation for y
y = x-4
y = 7-4
y = 3
so the width is 3m and the length is 7m