Problema Solution
A ball is thrown from an initial height of 5 feet with an initial upward velocity of 33ft/s. The ball's h(in feet) after t secconds is given by the following.
h=5+33T-16t^2
Find the value for t for which the ball's height is 21 feet.
Round your answer(s) to the nearest hundredth.
t=
Answer provided by our tutors
h=2+33t-16t²
when h=18 ft
then18=2+33t-16t²
→ 16t²−33t+16=0
t= [−(−33)±√{(−33) ²−4×16×16)}]/(2×16)
= [33±√{1089−1024}]/(32)
= [33±√{65}]/(32)
=1.283 , 0.779 seconds