Problema Solution
Find the vertex, the line of symmetry, and the maximum or minimum value of the quadratic function.
f(x) = -2x^2 + 2x + 1
Answer provided by our tutors
in the equation -2x2+2x+1,
a= -2, b=2, and c=1
the axis of symmetry is given by the line:
x = -b/2a, so substitute in 2 for b and -2 for a
x = -2/(2*-2) = -2/-4 = 2/4 = 1/2
so x = 1/2 is the axis of symmetry line.
the vertex will be on this line, since it is always on the line of symmetry, so substitute this into the equation for x to find the value for y of the vertex.
y = -2(1/2)2+2(1/2) + 1
y = -2(1/4) + 1 + 1
y = -1/2 + 2
y = 3/2
so the vertex is the point (1/2, 3/2)
3/2 is also the maximum value of the function; the vertex is the maximum point on the graph
this is because the value of a is negative, meaning that the graph opens downward.