Problema Solution
M is the mifpoint of AB. Find the coordinates of A given M(-6,-3/2) and B(-1,3)
Answer provided by our tutors
We assume A(m,n), B(-1,3)
So M((m-1)/2, (n+3)/2)
So
(m-1)/2 = -6
(n+3)/2 = -3/2
So
m = -11
n = -6
So
A(-11,-6)
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