Problema Solution
If you increase the numerator of a fraction by 3, and the denominator by 4, the value of the fraction will be doubled. The denominator of the orginal fraction is 1 more than the numerator. Find the original fraction.
Answer provided by our tutors
x+3/y+4 = 2x/y
y=x+1
step -2
(x+3)/(x+5) = (2x)/(x+1)
(x+3)*(x+1)=2x*(x+5)
x^2+4x+3 = 2x^2+10x
step3
x^2+6x-3=0
step-4
x^2 + 6x - 3 = 0
Solve using quadratic formula:
x = [- 6 ± √(48)]/2 = - 3 ± 2√3
From here we can solve y (y=x+1)