i'm assuming it says

x3+2x2-3x > 0

if this is not the correct problem just message me and i will redo it at no charge

factor out an x

x(x2+2x-3) > 0

factor the inside expression

x(x+3)(x-1) > 0

set each part > 0 and solve for x three times

x > 0

or x+3 > 0

x > -3

or x-1 > 0

x > 1

so x > 0

x > -3

x > 1

0 and 1 are greater than negative three, so you can write your answer as

x > -3