Problema Solution
a chemist mixes a 10% saline solution with a 20% saline solution to make 500 milliliters of a 16% saline solution.how many millileters of each solution does the chemist mix together?
Answer provided by our tutors
x + y = 500
0.10*x + 0.20 * y = 0.16*500
0.10*x + 0.20*(500-x) = 80
-0.10*x = -20
x = 200 ml = amount in first solution
y = 300 ml = amount in second solution