Problema Solution
How many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% solution to end up with a 25% solution?
Answer provided by our tutors
set up the equation:
0.10x + 0.50(40) = 0.25(40 + x)
0.1x + 20 = 10 + 0.25x
10 = 0.15x
x = 66.667 liters should be mixed with 40 L to make up the 25% solution