Problema Solution
How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20 L of a 72% solution?
Answer provided by our tutors
First set up the inaquality:
0.60x+0.75y = 0.72(20)
x+y=20
Then solve
The answer is
y=16
x=4
How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20 L of a 72% solution?
First set up the inaquality:
0.60x+0.75y = 0.72(20)
x+y=20
Then solve
The answer is
y=16
x=4