Problema Solution
a ball is thrown vertically upward with the initial velocity of 130ft/s. find its position and velocity at the end of 2,4,6 and 8 s. and scetch these positions and velocities on a piece of graph paper.
Answer provided by our tutors
The height is h, in the beginning, h=0
So we have
h = 130t - 0.5*32.15*t^2
v = 130 - 32.15t
When t = 2, h = 195.68 ft, v = 65.7 ft/s
When t = 4, h = 262.72 ft, v= 1.4 ft/s
When t = 6, h = 201.12 ft, v= -62.9 ft/s
When t = 8, h = 10.88 ft, v = -127.2 ft/s
The we can skectch them