The length of a dog house is to be 4 times its width in meters.The Doghouse will have an area of 64m^2, WHAT WILL THE DEMINSIONS BE?

let x - length

    y - width

x = 4y

xy = 64

4y x y = 64

y^2 = 16

y = sqrt 16

y = 4

x = 4y 

x = 4x4 = 16