Problema Solution
Your boundary points are -3, 0, and 1. This make three (four) possible intervals:
(-∞,-3)
(-3,0)
(0,1)
(1,∞)
You need to test a value in each of these three intervals, and show your work. The intervals with a positive result will be your answer. Please check out the posts titled Solving a quadratic inequality in the week 3 Problems and Solutions discussion for more help.
Answer provided by our tutors
The expression of f(x)= x(x+3)(x-1)
(1)
(-â,-3) Test value x = -5, the signs in x(x+3)(x-1)0
(3)
(0,1) Test x = 1/2, the signs in x(x+3)(x-1)0
So the solutions for f(x)0 is (-3,0)U(1,â)