3 1og5(3x + 1) – 2 1og5(2x – 1) – log5 x

Solution:

3 1og5(3x + 1) - 2 1og5(2x - 1)- log5 x

= log5(3x+1)^3 -log5(2x-1)^2 -log5x

= log5 (3x+1)^3/[x(2x-1)^2]

So the result is log5 {(3x+1)^3/[x(2x-1)^2]}