Problema Solution
Two buses leave towns 1090km apart at the same time and travel toward each other. One bus travels 20km/h slower than the other. If they meet in 5 hours, what is the rate of each bus?
Answer provided by our tutors
Let x = the rate of the slower bus.
5(x) + 5(x+20) = 1090
5x + 5x + 100 = 1090
10x + 100 = 1090
10x = 990
x = 99
Therefore, the slower bus goes 99 km/h and the faster bus goes 119 km/h.