Problema Solution
If 2 is added to the numerator and to the denominator of a fraction, the value becomes 0.9. If 3 is subtracted from both numerator and denominator, the value of the fraction becomes 0.8. What is the original fraction?
Answer provided by our tutors
Lets make A = to the numerator and B = to the denominator.
(A+2)/(B+2)=.9 (A-3)/(B-3)=.8
then we can solve for A, (A+2)=.9(B+2)= .9B+1.8
A=.9B-.2 plug A into the second equation and we get ((.9B-.2) -3)/(b-3)=.8
solve the equation and then you get B=8
Plug 8 into (A+2)/(B+2)=.9
then you can solve for A and get A= 7
therefor; the oroginal function is 7/8