Problema Solution
How many gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antifreeze?
Answer provided by our tutors
let x be the gallons of a 70% antifreeze
we have: (x*70%+ 80*25%)/(x+80)=60%
=> (0.7x+20)/(x+80)=0.6
=> x=280
so 280 gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antifreeze