Problema Solution
A swing is observed to rise to a maximum height of 1.5m above its lowest point. How fast is it going at its lowest point? Ignore friction and air resistance.
Answer provided by our tutors
1/2mv^2=mgh.
v^2=2gh.
v=sqrt(2gh).
=Sqrt(2*9.81*1.5).
=5.42 m/sec.