Problema Solution
david has scores of 82,73,80 &97 on his tests. use an inequality to find the minimum score he can make on his final exam to pass the course wiyth an average of 62 or higher.given that the final exam counts as 3 tests.
Answer provided by our tutors
Scores of David = 82, 73, 80, 97
Total of the scores obtained = 332
Let the score in the final exam = x
Final is counted as three tests
=> Total of all his tests = 332 + 3x
Average required = 62
=> Total number of tests = 4 + 3 = 7
=> 332 + 3x >= 62*7
=> 332 + 3x >= 434
=> 3x >= 102
=> x >= 34