Problema Solution
An object is launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. The equation for the object's height s at time t seconds after launch is s(t)+-16t^2 + 64t+80. What is the maximum Height of the object? What is the domain and range?
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s(t)+-16t^2 + 64t+80
the maximum Height of the object
s'(t) = -32t+64
for maxima
s'(t)=0
-32t=-64
t=2
s(2)=-16*4+128+80