Problema Solution
A baseball player strikes a 0.25 kg ball moving at 15m/s and sends it backward with a velocity of 25m/s. The ball is in contact with the bat for 0.05 sec. Find the magnitude of the impulse and the average force on the ball exerted by the batter.
Answer provided by our tutors
mass= .25 kg
initial velocity = 15 m/sec
final velocity = 25 m/sec
impulse= change in momentum
=> impulse = mass (final velocity -initial velocity)
= .25(25- (-15))
= .25*40
= 10 N-sec