Problema Solution
A rectangular sign has a width that is 4 feet less than the length. The overall perimeter of the sign is 32 feet. What is the length?
Answer provided by our tutors
Solve this equation algebraically to find the length of the rectangle:
P=2L+2W
Since the perimeter is twice the "length + width" we have:
2(L+L-2)=32
solving for L:
2(L+L-2)=32
(2L-2)=16
2(L-1)=16
L-1=8+L=9 inches.