Problema Solution
Write the slope-intercept equation for the line that passes
through (10,12) and is perpendicular to 5x+8y=1.
Answer provided by our tutors
(10,12) and is perpendicular to 5x+8y=1.
from 5x+8y = 1
8y = -5x+1
y = (-5/8)x+1/8
slope is -5/8
in perpendicular, new slope is 8/5
then, point (10,12)
y = mx+b,
12 = (8/5)(10) + b ==> b -4
hence, y - (8/5)x-4 answer