Problema Solution
A radiator contain 6.3l of antifreeze and water.The mixture is 30% of antifreeze.how much of this mixture should be drain to place pure antifreeze so that there will be a mixture 0f 50%antifreeze.
Answer provided by our tutors
alcohol -alcohol + alcohol = alcohol
0.30*6.3 -0.30x + 1.00x = 0.50*6.3
Multiply thru by 100 to get:
30*6.3 - 30x + 100x = 50*6.3
70x = 20*6.3
x = (2/7)6.3
x = 1.8 Liters