Problema Solution
The sum of 3 consecutive interral numbers is 117. Find the numbers
Answer provided by our tutors
x+(x+1)(x+2)=117
x+x+1+x+2=117
3x + 3 = 117
3x = 114
x = 38
38+1 = 39
38+2 = 40
Check 38+39+40 = 117
so three consecutive integral numbers are 38 ,39 and 40