Problema Solution
there are 50 grams of curium-245 which has a half-lige of 9300 years. how many grams will remain after 46500 years
Answer provided by our tutors
N=N exp(-0.693*t/thalf)
or N = 50* exp(-0.693*46500/9300)
or N=50* exp(-3.465)
or N=50*0.0312
or N = 1.56 gms
SO 1.56 gm will be lest