Problema Solution

Graph y=-x2(squared)-5x+3 on the standard axes. find the x-intercepts, y-intercept, and vertex. Determine whether the vertex is a relative maximum or a relative minimum.

Answer provided by our tutors

For x-intercept, let y=0, using quadratic formula: x = [-5 - sqrt(37)]/2 and x=[-5 + sqrt(37)]/2

x-intercepts: ([-5 - sqrt(37)]/2, 0) and ([-5 + sqrt(37)]/2, 0)

For y-intercept, let x =0, then y = 3

y-intercept:(0,3)

vertex (-b/2a, -delta/4a) = (-b/2a, -(b^2 -4ac)/4a)= (5/2, 37/4)

maximum since a =-1 <0