Problema Solution
Two friends live 2.2 miles apart along the same road. If they walk toward each other at rates that differ by 1/2 mph and meet 24 minute later, how fast is each person walking?
Answer provided by our tutors
x-y=0.5.
x*0.4+y*0.4=2.2.
4x+4y=22.
2x+2y=11.
2(0.5+y)+2y=11.
1+4y=11.
4y=10.
y=10/4.
=2.5 mph.
x=0.5+y=3 mph.
THe sppeds of two friends are 2.5 mph, 3 mph.