Problema Solution
Four times the smaller of two consecutive odd integers is the same as 73 less than 5 times the larger. Find the integer.
Answer provided by our tutors
4(2x + 1) = 5(2x + 3) - 73
8x + 4 = 10x + 15 - 73
8x + 4 = 10x - 58
8x = 10x - 62
-2x = -62
x = 31
so 2x + 1 = 2(31) + 1 = 62 + 1 = 63
so the integers are 63 and 65