Problema Solution
Five times the smallest of three consecutive even integers is 10 more than twice the largest. Find the integers.
Answer provided by our tutors
5X=2(X+4)+10
5X = 2X+8+10
3X = 18
X=6
Te integers are 6,8,10.
Five times the smallest of three consecutive even integers is 10 more than twice the largest. Find the integers.
5X=2(X+4)+10
5X = 2X+8+10
3X = 18
X=6
Te integers are 6,8,10.