Problema Solution
one number is five more than twice another. if their sum is increased by ten, the result is forty-eight. find the numbers.
Answer provided by our tutors
X + 2X + 5 + 10 = 48
3X = 33
X = 11
SO OTHER NUMBER = 27
one number is five more than twice another. if their sum is increased by ten, the result is forty-eight. find the numbers.
X + 2X + 5 + 10 = 48
3X = 33
X = 11
SO OTHER NUMBER = 27