Problema Solution
What three consecutive even integers have a sum of -36?
Answer provided by our tutors
Let the three consecutive integers be (a-1), a and (a+1)
The sum of the three consecutive integers is -36
Therefore (a-1)+ a + (a+1)= -36
(a+a+a)+(-1+1) = -36
3a = -36 ==>a = -12