Problema Solution
Suppose 4000 bacteria are present at time t=0
Then t minutes later, the number of bacteria present will be N(t)=4000(2)t/30(squared)
Find the bacteria present after 15 mintues and 90 minutes
Answer provided by our tutors
N(t) = 4000*(2)^(t/30)
if t=15
N(15)=4000*2^(0.5) = 4000*1.414 = 5656.85 = 5657 (rounded)
N(90) = 4000*2^(90/30) = 4000*8 = 32000