Problema Solution

1.) The ten digits of a two-digit number is 4 more than the units digit. If the sum of the digit is 5 less than one-fifth of the number.Find the number.

2.) The sum of the digits of a two digit number is 9. The number with the digit interchanged is 6 times the sum of the digits. Find the original number.

3. ) The units digit of a two-digit number is four time the ten digit. When the digit are reversed, the new number is 2 less than thrice the original number. Find the original number.

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Answer provided by our tutors

(1) Ten digit:(x+4), unit digit: x

5(x+4+x+5)=10(x+4)+x

x = 5

So the number is 95

(2)

Ten digit:(9-x), unit digit: x

6(9-x+x)=10(9-x)+x

x = 4

So the number is 54

(3)

Ten digit:x, unit digit: 4x

2(10x+4x) = 2 + 40x+x

So x = 2

The original number is 28