Problema Solution
DAVID IS TWICE AS OLD AS HIS DAUGHTER. IN 14YRS., DAVID'S AGE WILL BE THREE TIMES WHAT HIS DAUGHTER'S AGE WAS 6YRS. AGO. HOW OLD ARE THEY NOW?
Answer provided by our tutors
D = 2A
D + 14 = 3(A - 6)
substitute the first into the second
2A + 14 = 3(A - 6)
2A + 14 = 3A - 18
-A + 14 = -18
-A = -32
A = 32
so D = 2A
D = 2(32)
D = 64
so David is currently 64 and his daughter is currently 32