Problema Solution
If n(A) = 26, n(B) = 26, n(C) = 24, n(A B) = 8, n(A C) = 11, n(B C) = 8, and n(A B C) = 54, find n(A B C)
Answer provided by our tutors
Find n(A+B+C), right? or find n(ABC)??
We have,
n(A+B+C) = n(A)+n(B)+n(C)- [n(AB)+n(AC)+n(BC)] + n(ABC)
= 26+26+24- (8+11+8)+54
= 103