Problema Solution
A and B can do 1 work in 72 days working together. C alone work for last 20 days, it is finished in 80 days . In how many days c finish whole work alone
Answer provided by our tutors
a + b = 72 days
let work be 100
hence in one day they can do = 100/72
in 60 days =(100/72) * 60
work remained = 100 - (100/72) *60= 16.67 which is done by c in 20 days.
16.67 work c can do in = 20 days
1 work c can do in = 20/16.67
100 work c can do in = (20/16.67) * 100 = 120 days approx.