Problema Solution

A minor league baseball team 96 games in a season. If the team won 15 more than twice as many games as they lost, how many wins and losses did the team have?

Answer provided by our tutors

let W be the number of game won and L be the number of game lost

"A minor league baseball team 96 games in a season" means number of game won + number of game lost = 96

hence, W + L = 96 (*)

"the team won 15 more than twice as many games as they lost"

means W = 15 + 2L (**)

now, plugging (**) into (*) to solve for L first

W + L = 96

=> (15 + 2L) + L = 96

<=> 15 + 3L = 96

<=> 3L = 81

<=> L = 27

To find W, we can plug L = 27 into either (*) or (**)

W = 15 + 2 x27

  = 69

The answer is

W = 69 & L = 27