Problema Solution
A minor league baseball team 96 games in a season. If the team won 15 more than twice as many games as they lost, how many wins and losses did the team have?
Answer provided by our tutors
let W be the number of game won and L be the number of game lost
"A minor league baseball team 96 games in a season" means number of game won + number of game lost = 96
hence, W + L = 96 (*)
"the team won 15 more than twice as many games as they lost"
means W = 15 + 2L (**)
now, plugging (**) into (*) to solve for L first
W + L = 96
=> (15 + 2L) + L = 96
<=> 15 + 3L = 96
<=> 3L = 81
<=> L = 27
To find W, we can plug L = 27 into either (*) or (**)
W = 15 + 2 x27
= 69
The answer is
W = 69 & L = 27